I'm migrating code from Lasso 8 to 9. I can't find any
documentation to explain what is going on. In 8, params passed
to a method for a custom type are iterable. In the two 9
samples, params has a size, but it appears to be not iterable.
Is this a bug in 9?

=====================Lasso 8
=================== [
define_type('mytype');

define_tag('_unknowntag');
local('result');
if(params->size);
iterate(params,local('i'));
#result += #i + ' | ';
/iterate;
/if;
return(tag_name + ' | ' #result);
/define_tag;

/define_type;

local('a') = mytype;
#a->method('foo' = 'bar', 'moo');
]
=>
method | pair: (foo)=(bar) | moo |

=====================Lasso 9 Original
=====================[
define_type('mytype');

define_tag('_unknowntag');
local('result' = string);
if(params->size);
iterate(params,local('i'));
#result += #i + ' | ';
/iterate;
/if;
return(tag_name + ' | ' #result);
/define_tag;

/define_type;

local('a') = mytype;
#a->method('foo' = 'bar', 'moo');
]
=>
method |

=====================Lasso 9 Modified
=================== [
define_type('mytype');

define_tag('_unknowntag');
local('result' = string);
local(wtflolz_lasso9 = params)
if(params->size);
iterate(#wtflolz_lasso9,local('i'));
#result += #i + ' | ';
/iterate;
/if;
return(tag_name + ' | ' #result);
/define_tag;

/define_type;

local('a') = mytype;
#a->method('foo' = 'bar', 'moo');
]
=>
method |(foo = bar) | moo |

--steve

-- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- -- --
-- --
Steve Piercy Web Site Builder
Soquel, CA
<web@StevePiercy.com> <http://www.StevePiercy.com/>


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